<math>Q_{max, m}=\frac{80 mm/hr\times 300\ m^{2}\times \left (\frac{0.975\ m}{0.6\ m} \right )\times 2}{3600\ s/hr}=21.6\ L/s</math> | <math>Q_{max, m}=\frac{80 mm/hr\times 300\ m^{2}\times \left (\frac{0.975\ m}{0.6\ m} \right )\times 2}{3600\ s/hr}=21.6\ L/s</math> |