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| [[file:Hydraulic radius.png|thumb|Three footprint areas of 9 m<sup>2</sup>.<br> | | [[file:Hydraulic radius.png|thumb|Three footprint areas of 9 m<sup>2</sup>.<br> |
| From left to right x = 12 m, x = 20 m]]<br> | | From left to right x = 12 m, x = 20 m]]<br> |
| For some geometries (e.g. particularly deep facilities or linear facilities), it preferable to account for lateral infiltration. | | For some geometries, particularly deep or linear facilities, it desirable to account for lateral drainage, out the sides of the storage reservoir. |
| The 3D equation make use of the hydraulic radius (''A<sub>p''/''x''), where ''x'' is the perimeter (m) of the facility. <br> | | The following equation makes use of the hydraulic radius (''A<sub>r''/''x''), where ''x'' is the perimeter (m) of the facility. <br> |
| '''Maximizing the perimeter of the facility directs designers towards longer, linear shapes such as [[infiltration trenches]] and [[bioswales]].'''<br> | | '''Maximizing the perimeter of the water storage reservoir of the facility will enhance drainage performance and directs designers towards longer, linear shapes such as [[infiltration trenches]] and [[bioswales]].''' See illustration for an example.<br> |
| <br> | | <br> |
| To calculate the time (''t'') to fully drain the facility: | | To calculate the time (''t'') to fully drain the facility assuming three-dimensional drainage: |
| <math>t=\frac{nAp}{f'x}ln\left [ \frac{\left (d+ \frac{Ap}{x} \right )}{\left(\frac{Ap}{x}\right)}\right]</math> | | <math>t=\frac{nAp}{f'x}ln\left [ \frac{\left (d+ \frac{Ap}{x} \right )}{\left(\frac{Ap}{x}\right)}\right]</math> |
| Where "ln" means natural logarithm of the term in square brackets | | Where "ln" means natural logarithm of the term in square brackets |