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<math>W_T=0.817\times(0.08)^{0.42}\times(0.02)^{0.3}\left (\frac{1}{0.013\times0.03}\right)^{0.6}=9.71\ m</math>
<math>W_T=0.817\times(0.08)^{0.42}\times(0.02)^{0.3}\left (\frac{1}{0.013\times0.03}\right)^{0.6}=9.71\ m</math>
The proportion of water entering the bioretention cell under these flow conditions would be::
<math>R_c=1-\left ( 1-\frac{3}{9.71} \right )^{1.8}</ma
==Curb cuts Gallery==
==Curb cuts Gallery==