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→Thornthwaite Mather method
Line 13:
Line 13:
<math>PET_{uncorrected}=1.6\cdot \left ( \frac{10\cdot T}{I} \right )^{\alpha }</math>
<math>PET_{uncorrected}=1.6\cdot \left ( \frac{10\cdot T}{I} \right )^{\alpha }</math>
where: α = 6.75 x 10<sup>-7</sup>''I<sup>3</sup>'' - 7.71 x 10<sup>-5</sup>''I<sup>2</sup>''+ 0.0179''I'' + 0.49
where: α = 6.75 x 10<sup>-7</sup> ''I<sup>3</sup>'' - 7.71 x 10<sup>-5</sup> ''I<sup>2</sup>''+ 0.0179 ''I'' + 0.49