Changes

:<math>V_{f}=1.7\times 0.8\times 0.6\times 1=0.816\ m^{3}</math>

:<math>V_{f}=1.7\times 0.8\times 0.6\times 1=0.816\ m^{3}</math>

The area required to keep the maximum head of water within the forebay to 0.15 m is calculated as:

The area required to keep the maximum head of water within the forebay to 0.15 m is calculated as:

:<math>A_{f}=\frac{0.816}{0.1}=8.16\ m^{2}</math>

:<math>A_{f}=\frac{0.816}{0.15}=5.44\ m^{2}</math>

The area required to settle the 1 mm particles is calculated as:

The area required to settle the 1 mm particles is calculated as:

:<math>A_{f}=120\times 0.1 = 12\ m^{2}</math>

:<math>A_{f}=120\times 0.1 = 12\ m^{2}</math>