8,254
edits
Changes
Jump to navigation
Jump to search
mLine 19:
Line 19:
→To calculate the invert of the underdrain from the base of the reservoir
<math>d_{s, max}=\frac{f'\times t}{0.4}</math>
<math>d_{s, max}=\frac{f'\times t}{0.4}</math>
{{Plainlist|1=Where:
{{Plainlist|1=Where:
*''f''' = [[Design infiltration rate]] (mm/hr), and
*''f''' = Design infiltration rate (mm/hr), and
*''t'' = [[Drainage time]] (hrs), e.g. 96 hours, check local regulations for drainage time requirements.
*''t'' = [[Drainage time]] (hrs), e.g. 96 hours, check local regulations for drainage time requirements.
*''0.4'' = Void ratio of [[Reservoir aggregate|clear stone]]}}
*''0.4'' = Void ratio of [[Reservoir aggregate|clear stone]]}}